Pergunta de entrevista da empresa Jet
Algorithm to determine if a string is palindrome.
Resposta da entrevista
Sigiloso
22 de out. de 2018
def isPalindrom(s): for i in range(0,len(s)//2): if s[i] != s[len(s)-i-1]: return 'NO' return 'YES'
Algorithm to determine if a string is palindrome.
Sigiloso
def isPalindrom(s): for i in range(0,len(s)//2): if s[i] != s[len(s)-i-1]: return 'NO' return 'YES'