Pergunta de entrevista da empresa Arity

Code Fibonacci sequence

Resposta da entrevista

Sigiloso

15 de nov. de 2018

In R: fibon.Seq<- function(n){ recurring.Mat <- matrix(c(0,1),nrow=1) A <- matrix(c(0,1,1,1),nrow = 2) for(i in 1:n){ recurring.Mat <- recurring.Mat%*%A } return(recurring.Mat[2]) }