Pergunta de entrevista da empresa Zalando

For a given array count combination of pairs of (x,y) whose sum is N.

Respostas da entrevista

Sigiloso

17 de mar. de 2015

int[] list = {7,6,2,3,4,5}; int N=9; int count=0; for(int i=0;i

5

Sigiloso

27 de ago. de 2013

Three solutions I gave. 1. Sort the array in O(nlogn). Min and Max as two indices. Count=0 Loop if A[Min]+A[Max]N Decrement (Max) else Increment(Count) End 2. Using extra space and count sort if the minima and maxima of array sets are in a given range. Max absolute negative number subtracted to keep numbers in positive number space. Loop if Memory[N- A[i]- Min] Increment(Count) End 3. Create a Hashset/Hashtable. Look for N-A[i] and increment count if found. Loop if Get(N- A[i]) Increment (Count) else Push(A[i]) End

Sigiloso

26 de jul. de 2014

the complexity of ur solution is not so good you can do better

Sigiloso

10 de ago. de 2014

couldn't you just look through the array and check the sum of each combination and then check against a hashtable?! I don't understand why you have to do all the sorting stuff!