Give an array of numbers find the max difference.

Question

Sigiloso · Accepted Answer

int maxDiff(int[] array) {
    if (array.length == 0) {
        return 0;
    }
    
    int min = Integer.MAX_VALUE;
    int max = Integer.MIN_VALUE;
    for (int a : array) {
        min = Math.min(a, min);
        max = Math.max(a, max);
    }
    return max - min;
}

Anonymous · Answer

2, 
  '2' => 4, 
  '3' => 6, 
  '4' => 24, 
  '5' => 10, 
  '6' => 49, 
  '7' => 14, 
  '8' => 19
);

$max = max($arr);
$maxArr=[];

foreach ($arr as $k => $val) {

	if($val > 0) {
		$diff = ($max - $val);
		if($diff > 0) {
			$maxArr[] = ($max - $val);
		}
	}
}

echo min($maxArr);

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