Implement doLaundry([wash, dry, fold])
Suppose we have the following functions
function wash(callback) {
setTimeout(function () {
console.log('wash');
callback();
}, 3000);
}
function dry(callback) {
setTimeout(function () {
console.log('dry');
callback();
}, 2000);
}
function fold(callback) {
setTimeout(function () {
console.log('fold');
callback();
}, 1000);
}

Question

Implement doLaundry([wash, dry, fold])
Suppose we have the following functions
function wash(callback) {
  setTimeout(function () {
    console.log('wash');
    callback();
  }, 3000);
}
function dry(callback) {
  setTimeout(function () {
    console.log('dry');
    callback();
  }, 2000);
}
function fold(callback) {
  setTimeout(function () {
    console.log('fold');
    callback();
  }, 1000);
}

Sigiloso · Accepted Answer

const doLaundry = ([wash, dry, fold]) => wash(() => dry(() => fold(() => {})))

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