Pergunta de entrevista da empresa Meta
Print all nodes of tree in order .
Resposta da entrevista
Sigiloso
23 de jan. de 2019
def inOrder(root): if root.left != None: inOrder(root.left) print(root.val) if root.right != None: inOrder(root.right)
Print all nodes of tree in order .
Sigiloso
def inOrder(root): if root.left != None: inOrder(root.left) print(root.val) if root.right != None: inOrder(root.right)