Pergunta de entrevista da empresa Meta
Square root of x
Resposta da entrevista
Sigiloso
25 de out. de 2016
def sqrt(x): min = 1 max = x if x 0.01: if mid**2 > x: max = mid else: min = mid mid = min+ (max - min)/2 return mid
1
Square root of x
Sigiloso
def sqrt(x): min = 1 max = x if x 0.01: if mid**2 > x: max = mid else: min = mid mid = min+ (max - min)/2 return mid