The hardest problem posed was the C# function I had to write. Write a function that accepts a character parameter such as "8" and then returns its digit value which would be 8 in this case. You cannot use any helper functions, casting or conversion functions.
int ParseCharToInt(char c)

Question

The hardest problem posed was the C# function I had to write. Write a function that accepts a character parameter such as "8" and then returns its digit value which would be 8 in this case. You cannot use any helper functions, casting or conversion functions. 
int ParseCharToInt(char c)

simple · Accepted Answer

int GetDigitFromInput(char input){if (('9' - input) < 0)return -1;// or throw new Exception("Numeric Char Only");
return input - '0';}

Sigiloso · Answer

well.. this can be a little bit of a cheat but one character can only be from 0 to 9, +ve numbers. A simple dictionary like charMap should do the trick. This will work in O(1) time complexity and O(n) or O(c) space complexity.

Sigiloso · Answer

You could also use a switch statement:

int ParseChar(char number)
{
   switch(number)
   {
      case '0':
         return 0;
      case '1':
         return 1;
      case '2':
         return 2;
      case '3':
         return 3;
        etc..      
   }

   throw new Exception('Invalid input");
}

If you could assume only valid inputs, then you could just subtract '0' from the value:

int ParseChar(char number)
{
   return number - '0';
}

Sigiloso · Answer

Even Google didn't have the answer to this problem.

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