Pergunta de entrevista da empresa Rockwell Automation
What is the square root of i.
Resposta da entrevista
Sigiloso
31 de dez. de 2014
Let x + iy = sqrt( i )..........(1) Squaring and using i^2 = -1, ( x^2 - y^2 ) + ( 2xy) i = i = 0 + 1 i => x^2 - y^2 = 0 and y = 1 / ( 2x). Solving simultaneously, x = y = +/- 1/ (sqrt 2) From (1), sqrt( i ) = +/- ( 1/ sqrt 2 ) ( 1 + i ).