Pergunta de entrevista da empresa InnovationM

find frequency of every word in string

Respostas da entrevista

Sigiloso

8 de mai. de 2020

import java.util.HashMap; public class FrequencyOfEachWord { public static void main(String[] args) { String str = "aaddrfshdsklhio"; char[] arr = str.toCharArray(); HashMap hMap = new HashMap(); for(int i= 0 ; i< arr.length ; i++) { if(hMap.containsKey(arr[i])) { int count = hMap.get(arr[i]); hMap.put(arr[i],count+1); } else { hMap.put(arr[i],1); } } System.out.println(hMap); } }

Sigiloso

8 de mai. de 2020

import java.util.HashMap; public class FrequencyOfEachWord { public static void main(String[] args) { String str = "aaddrfshdsklhio"; char[] arr = str.toCharArray(); HashMap hMap = new HashMap(); for(int i= 0 ; i< arr.length ; i++) { if(hMap.containsKey(arr[i])) { int count = hMap.get(arr[i]); hMap.put(arr[i],count+1); } else { hMap.put(arr[i],1); } } System.out.println(hMap); } }

Sigiloso

8 de jul. de 2019

package sinha; import java.util.HashMap; import java.util.Scanner; public class Duplicate_Word2 { static void getString(String str) { String[]s=str.split(" "); int count; HashMap hm=new HashMap(); for (int i=0;i

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