Pergunta de entrevista da empresa CarltonOne Engagement
$sql = "SELECT * FROM table as a WHERE a.id ={ $id }"; What is wrong with the code ?
Resposta da entrevista
Sigiloso
5 de nov. de 2018
SQL Injection vulnerability with $id.
$sql = "SELECT * FROM table as a WHERE a.id ={ $id }"; What is wrong with the code ?
Sigiloso
SQL Injection vulnerability with $id.