The company visited our campus for 3 hardware roles, physical design role, SOC verification role and FPGA design role. I was interviewed by the SOC verification team. Round 0 - Online Assessment(with negative marking) > Section A -> Aptitude - 30 mins, 20 Questions -> easy to moderate level > Section B -> C programming - 30 mins, 20 Questions -> moderate level > Section C -> Digital - 30 mins, 20 Questions -> moderate to hard level. Round 1 - 20 mins approx > Asked to introduce myself > Discussion on my projects > Told about the role they came for and asked me if I am okay with that role. > Why Qualcomm and where do I see myself or what are my career plans for the next 5 years. > Asked array based C programming questions like, merge sort algo, finding second largest element in a array, time complexity. Round 2 - 40 mins approx > Discussed about the role > Ring oscillator > Setup time and hold time > What is STA > Binary search algo, pseudo code and time complexity > Negative feedback opamp > Summing circuit using opamp and what happens if we interchange the inverting and non inverting terminals > Suppose there are 2 FFs having same clock, then will clock reach exactly at the same time. If not why and how it can be reduced. > clock skew, clock uncertainty and clock jitter. > 2-FF synchroniser > What are cache lines > What are dirty lines and dirty bit > What is a watch dog timer > what is Cache memory, what is its need and importance. > difference b/w SRAM and DRAM. > Why SRAM is used in Cache > Verilog code for AND gate using MUX > Is Stack LIFO or FIFO > Is SRAM volatile or non-volatile, why ? > Aptitude question 1: There are 100 gates and 100 people, all the gates are initially closed, the 1st person will flip the 1st, 2nd, 3rd, ... till 100th gate. 2nd person will flip the 2nd, 4th, 6th, .. 100th gate, 3rd person will flip 3rd, 6th, 9th, ... 99th gate, and so on till 100th person. After all 100 people do this, how many gates will be open ? (flip -> close if open and open if close) Answer: floor(sqrt(N)), where N = total no. of people. The logic is that the rth gate will be open at the end if r is a perfect square. > Aptitude question 2: In a cube shaped room with side 'a', there is an ant at one of the corner, it can't fly obviously and it can move on the floor, the walls, etc. So what is the minimum distance it has to travel so as to reach the diagonally opposite corner of the cube. Answer: sqrt(5)*a Hint given: open up the cube into a 2D plane, then you can see the shortest path HR round - 5-10 mins > Asked about myself, my skills, hobbies, family, strengths. > Preferred job location.