Candidatei-me online. Fiz uma entrevista na empresa TikTok.
Entrevista
I received a Hackerrank coding assessment (4 questions, 120 min.). The questions were fine (medium - hard questions). But I decided not to finish the assessment for two reasons.
1. It made you turn your webcam on for surveillance.
2. It didn’t allow you to use the Java API for reference (so it pretty much wanted you to know everything from the top of your head).
It’s pretty obnoxious for any coding assignment for those to be the conditions.
Perguntas de entrevista [1]
Pergunta 1
Four Hackerrank Medium - Hard questions. 120 mins for all four questions.
Fiz uma entrevista na empresa TikTok (San Francisco, CA).
Entrevista
OA - 1 arrays Medium, 1 Trie Hard. I had 45 minutes to complete that. I was able to do the medium in about 15-20 minutes but I am not that great with trie ds so I was not able to finish.
Four Round Process
Phone Interview with Human Resources
Coding Round; 1 DSA Leetcode Medium Q
Coding Round: 2 DSA Leetcode Medium Q
Manager Round: System Design Q and behavioural Q
It took about four weeks from application to offer, longer than I initially expected. The initial phone screen was straightforward, covering my resume and some basic algorithms. Then came the technical rounds, which were challenging. One question on minimum window substrings had me diving into a sliding-window approach using pointers and hashmaps. Funny enough, I recognized it mid-round as something I’d practiced on PracHub just days before. After a final system design discussion, I received the offer and happily accepted.
Perguntas de entrevista [1]
Pergunta 1
Given two strings s and t, return the minimum window substring of s that contains every character of t including duplicates, or an empty string if no such window exists. Walk through the sliding-window approach using two pointers and a character-frequency hashmap, analyze the O(|s| + |t|) time complexity, and discuss how to adapt it when t contains characters not present in s or when s arrives as a stream that cannot be fully buffered.
