Candidatei-me online. Fiz uma entrevista na empresa TikTok.
Entrevista
it took 3 round, first one wiz HR, second and third one wiz tech recruiters. not only asked you to code, but also asked a lot of OS questions. Among these two recruiters, one was good, the other one was bad. He said he just got this company like for 3 months and looked like he didn't care anything. During the interview, he constantly checked his email, his phone, and even leave the meeting while I was writing code for he said he had to reconnect his internet.
Perguntas de entrevista [1]
Pergunta 1
OS fundamental questions
Algorithms and leetcode problems
Fiz uma entrevista na empresa TikTok (San Francisco, CA).
Entrevista
OA - 1 arrays Medium, 1 Trie Hard. I had 45 minutes to complete that. I was able to do the medium in about 15-20 minutes but I am not that great with trie ds so I was not able to finish.
Four Round Process
Phone Interview with Human Resources
Coding Round; 1 DSA Leetcode Medium Q
Coding Round: 2 DSA Leetcode Medium Q
Manager Round: System Design Q and behavioural Q
It took about four weeks from application to offer, longer than I initially expected. The initial phone screen was straightforward, covering my resume and some basic algorithms. Then came the technical rounds, which were challenging. One question on minimum window substrings had me diving into a sliding-window approach using pointers and hashmaps. Funny enough, I recognized it mid-round as something I’d practiced on PracHub just days before. After a final system design discussion, I received the offer and happily accepted.
Perguntas de entrevista [1]
Pergunta 1
Given two strings s and t, return the minimum window substring of s that contains every character of t including duplicates, or an empty string if no such window exists. Walk through the sliding-window approach using two pointers and a character-frequency hashmap, analyze the O(|s| + |t|) time complexity, and discuss how to adapt it when t contains characters not present in s or when s arrives as a stream that cannot be fully buffered.