Pergunta de entrevista da empresa LinkedIn

Find indices start and end for a particular value in a sorted integer array with duplicates

Respostas da entrevista

Sigiloso

26 de ago. de 2016

Explained simple way to do this using linear search and binary search and coded up using binary search

Sigiloso

19 de dez. de 2016

public int firstOccur(int[] arr, int k) { if (arr == null || arr.length combinedOccur(int[] arr, int k) { BinarySearchOccurences obj = new BinarySearchOccurences(); int startIndex = obj.firstOccur(arr, k); int endIndex = obj.lastOccur(arr, k); if (startIndex == -1 || endIndex == -1) { throw new IllegalArgumentException("k does not exist in array"); } ArrayList result = new ArrayList(); result.add(startIndex); result.add(endIndex); return result; }

Sigiloso

19 de dez. de 2016

public int firstOccur(int[] arr, int k) { if (arr == null || arr.length combinedOccur(int[] arr, int k) { BinarySearchOccurences obj = new BinarySearchOccurences(); int startIndex = obj.firstOccur(arr, k); int endIndex = obj.lastOccur(arr, k); if (startIndex == -1 || endIndex == -1) { throw new IllegalArgumentException("k does not exist in array"); } ArrayList result = new ArrayList(); result.add(startIndex); result.add(endIndex); return result; }