Write a code to for an input arithmetic equation to detect the braces and return the output in Binary i.e. for each opened braces there would be one closed braces.

2+((3-1)/8 ----- Output = False

2+((3-1)/8) -------- Output = True

Don't remember the exact wordings of the question.

Question

Write a code to for an input arithmetic equation to detect the braces and return the output in Binary i.e. for each opened braces there would be one closed braces.

2+((3-1)/8 ----- Output = False

 2+((3-1)/8) -------- Output = True

Don't remember the exact wordings of the question.

Sigiloso · Accepted Answer

a = "2+((3-1)/8"
b = a.codepoints.to_a

len = b.length
countopen = 0
countclose = 0
for i in 0..len-1

  if b[i] == 40
    countopen = countopen + 1
  end
  if b[i] == 47
    countclose = countclose + 1
  end
end

print "#{countopen}"
print "#{countclose}"

if countopen == countclose
  print "False"
else
  print "True"
end

solution to the problem in java · Answer

public class HelloWorld{

     public static void main(String []args){
        System.out.println("Hello World");
        
        test t1 = new test();
        System.out.println(t1.checkBraces("2+(()3-1)/8"));
     }
}


class test{
    
    public boolean checkBraces( String s1){
        
        char[] c1 = s1.toCharArray();
        int count = 0;
        for (int i=0; i

Sigiloso · Answer

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